xii) 2x\displaystyle ^{0}cos3x\displaystyle ^{0} কে x এর সাপেক্ষে অন্তরীকরণ করে পাই,

Calculas _img

xii) 2x\displaystyle ^{0}cos3x\displaystyle ^{0}
মনে করি,
y= 2x\displaystyle ^{0}cos3x\displaystyle ^{0}
x এর সাপেক্ষে অন্তরীকরণ করে পাই,
\displaystyle \frac{dy}{dx}=\displaystyle \frac{d}{dx}(2x\displaystyle ^{0}cos3x\displaystyle ^{0})

= \displaystyle \frac{d}{dx}(\displaystyle \frac{2\prod x}{180}cos\displaystyle \frac{3\prod x}{180})

=\displaystyle \frac{d}{dx}(\displaystyle \frac{\prod x}{90}cos\displaystyle \frac{\prod x}{60})

=\displaystyle \frac{\prod x}{90}.(-sin\displaystyle \frac{\prod x}{60}).\displaystyle \frac{\prod }{60}+cos\displaystyle \frac{\prod x}{60}.\displaystyle \frac{\prod }{90}

=\displaystyle \frac{\prod }{90}(cos\displaystyle \frac{\prod x}{60}\displaystyle \frac{\prod x}{60}sin\displaystyle \frac{\prod x}{60}) (ans):

Calculas _img

i) e\displaystyle ^{5x} sin\displaystyle x^{0}
মনে করি,
y=e\displaystyle ^{5x} sin\displaystyle x^{0}
x এর সাপেক্ষে অন্তরীকরণ করে পাই,
\displaystyle \frac{dy}{dx}=\displaystyle \frac{d}{dx}(e\displaystyle ^{5x} sin\displaystyle x^{0})

=\displaystyle \frac{d}{dx}(e\displaystyle ^{5x}.sin\displaystyle \frac{\prod x}{180}) তোমাদের জন্য

Post Author: showrob

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